feat: Added 50 Pow(x,n) for nodejs

- feat: Added using recursion for permuatation problem example in nodejs
This commit is contained in:
Aerex 2020-01-27 20:58:15 -06:00
parent 8dae9824b3
commit cf1d656aa5
3 changed files with 115 additions and 0 deletions

1
.gitignore vendored
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/.gtm/ /.gtm/
.vimspector.json

96
pow-x-n/nodejs/index.js Normal file
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/*
Implement pow(x, n), which calculates x raised to the power n (xn).
Example 1:
Input: 2.00000, 10
Output: 1024.00000
Example 2:
Input: 2.10000, 3
Output: 9.26100
Example 3:
Input: 2.00000, -2
Output: 0.25000
Explanation: 2-2 = 1/22 = 1/4 = 0.25
Note:
-100.0 < x < 100.0
n is a 32-bit signed integer, within the range [231, 231 1]
*/
const { assert } = require('../../util/js');
/**
* @param {number} x
* @param {number} n
* @return {number}
*/
var myPow = function(x, n) {
const isNeg = n < 0 ? true: false;
if (n === 0) {
return 1;
}
if (n === 1) {
return x;
}
if (n === -1) {
return 1/x;
}
const storedCalcs = {};
const recursivePow = (x, n) => {
if (n === 2) {
return isNeg ? (1/x * 1/x) : x * x;
}
if (n === 1) {
return isNeg ? 1/x : x;
}
if (n === 0) {
return 1;
}
const firstHalf = Math.floor(parseInt(Math.abs(n) / 2));
const secondHalf = Math.abs(n) - firstHalf;
if(storedCalcs[n]) {
return storedCalcs[n];
}
const result = recursivePow(x, firstHalf) * recursivePow(x, secondHalf);
storedCalcs[n] = result;
return result;
};
return recursivePow(x, n);
}
/* Test Case 1
* Input: 2.00000, 10
* Output: 1024.00000
*/
x = 2.00000;
n = 10;
sol = 1024.00000;
assert(myPow(x, n) == sol, 'Output: 1024.00000');
/* Test Case 2
* Input: 2.10000, 3
* Output: 9.261
*/
x = 2.10000;
n = 3;
sol = 9.261;
assert(myPow(x, n).toFixed(3) == sol, 'Output: 9.261');
/* Test Case 3
* Input: 2.00000, -2
* Output: 0.25
*/
x = 2.00000;
n = -2;
sol = 0.25;
assert(myPow(x, n) == sol, 'Output: 0.25000');

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const RecPermute = (soFar, rest) => {
if (rest.length === 0) {
console.log('result', soFar);
console.log('\n\n');
} else {
for (let i = 0; i < rest.length; i++) {
const remaining = rest.substring(0,i) + rest.substring(i+1);
console.log('r', remaining)
console.log('R', rest);
console.log('SF', soFar);
console.log('------');
RecPermute(soFar + rest[i], remaining);
}
}
};
x = 'abc';
RecPermute('', x);